MTB > execute 'nw2-1-3.mtb' MTB > # Bill Qualls MTB > # NW - Stats II - Lab 1 - #3 MTB > # This is NW2-1-3.MTB MTB > MTB > # 3. Invoices at a particular depot have amounts which follow a normal di > stribution MTB > # with a mean invoice of $110.70 and a standard deviation of $7.85. MTB > MTB > # Recall standard normal has mean=0 and stdev=1. MTB > # Since this is not a standard distribution, we need to specify mean and > stdev. MTB > # The cdf instuction gives the area to the left of x. MTB > # To get the area to the right of x, subtract cdf from 1. MTB > # To get the area between two x scores, subtract their cdfs. MTB > # Asign a constant to a variable starting with k: k1, k2, k3, ... MTB > MTB > MTB > # What percentage of invoices will be over $130.25? MTB > # Must use the cdf command and the normal subcommand. MTB > # Note the semicolon on the first line, indicating a subcommand MTB > # will follow, and a period on the second indicating end. MTB > # Reminder: for "over", subtract cdf from 1 MTB > cdf 130.25; SUBC> normal 110.70 7.85. 130.2500 0.9936 MTB > let k1 = 1 - 0.9936 MTB > print k1 K1 0.00639999 MTB > MTB > MTB > # What percentage of invoices will be below $91.50? MTB > # Reminder: for "below", no other calculation is needed. MTB > cdf 91.50; SUBC> normal 110.70 7.85. 91.5000 0.0072 MTB > print k1 K1 0.00639999 MTB > MTB > MTB > # What percentage of invoices will be between $87.25 and $118.30? MTB > # Reminder: for "between", subtract low cdf from high cdf. MTB > cdf 87.25; SUBC> normal 110.80 7.85. 87.2500 0.0013 MTB > cdf 118.30; SUBC> normal 110.80 7.85. 118.3000 0.8303 MTB > let k1 = 0.8303 - 0.0013 MTB > print k1 K1 0.829000 MTB > MTB > stop *** Minitab Release 8.21 *** Minitab, Inc. *** Storage available 16174